Stoichiometric point

The equivalence point, or stoichiometric point, of a chemical reaction occurs during a chemical titration when the amount of titrant added is equivalent, or equal, to the amount of analyte present in the sample. In some cases there are multiple equivalence points which are multiples of the first equivalent point, such as in the titration of a diprotic acid. A graph of the titration curve exhibits an inflection point at the equivalence point. A striking fact about equivalence is that in a reaction the equivalence of the reactants as well as products is conserved.

The end point (similar, but not the same as the equivalence point) refers to the point at which the indicator changes color in a colorimetric titration.

Career Aspects.

okays, here goes. 07:53pm
What i inspire is to become a Forensic Pathologist;
particularly in the area of law enforcements agencies which investigate cases of sudden, unnatural or violent death or serious crimes.
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some stuff i copied.
Duties:
Question and think logically to determine the cause of injury or death.
Examine victims of intoxication, child abuse and other offences.
Record your findings meticulously as they may be used in court.

Person qualities:
Good communication & people skills
motivated & able to work independently
Desire to protect public health & safety

Entry Requirements:
Bachelor of Medicine Bachelor of surgery (MBBS) from a recognised university
& registration with the Singapore Medical Council.

University Requirement:
Medicine(NUS):
H2 Chem, H2 Phy/Bio.
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dilemma. 08:14pm
okays, here's the problem. I just got information that the COP for Medicine in NUS is 80. That's like equivalent to 3 H2 A-grades, and 2 H1 As. sighs. Now i'm at a lost.

Not that i want to give up already, but i know it's practically not going to be easy to achieve. None the less i will still work towards my target, if all hope fails, i'll have to look into another field of career.. perhaps a scientific mathematician or a simple maths teacher?
hahas. guess i still have some research to do. =P
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now. 08:27pm
Hmmm. Hopefully the next few days i'll be able to plan my time well, still adapting to become more hardworking. hahas. Kays, time to continue on my next pile of work. chal.

"two roads, one decision."

weaknesses.

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heys people. hmmm, i guess it's time i reveal some facts about me already. i know this is blog is public, so i trust that you all can at least be sensible and not talk about it. thx. =)
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little background.
okay, here's the fact: i've lost touch with all i've learned in secondary school, i was from polytechnic to begin with before i entered MI. Having said so, there is nothing i can remember about topics until i do a recap of what i've learned 2 years back. =/

Currently, everything that i've learned so far is like so vague to me. The very much i can remember about o-lvl syllabus isn't alot, so practically i made a resolution to not be absent from any class, and to be attentive in each lesson too. I know that i cannot afford to lose any oppertunity to learn because i'm already am struggling in my work.
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solution.
Yeah i know i'm in the science-stream and i will certainly suffer through, that's why i'm starting to get tuitions for myself from a friend who just finished A-levels. Well, view it this way: I get cheaper/free tuitions; my 'tutor' gets some teaching experience. So it's like a win-win situation. haha.

But seriously i don't think it's really enough. I'll continue to source for more effective ways to cover my O & A-level syllabus at the same time. Not much time is left and i know this must start early as possible if i want things to work out nicely. i'm going to use these 3 years in MI efficiently, not going to waste anymore time.
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summary.
One thing i'm grateful for is that maths is my strong suit, so thankfully i can now put more focus on my 2 other H2s, Chem & Phy. But schedules nowadays don't end early. =/
its like on an average of 5pm then i get to be free on weekdays, and weekend mornings are occupied with external CCA and service, so i don't get a full day to rest. hahas.

Wouldn't consider this hard-working cause experiencing some problems here and there.. but no matter what i will still up hold the given tasks. All i pray is strength to do a good-job where ever i am. =)
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ending. 22march, 6:08pm.
So Teachers, Lecturers and fellow-schoolmates, do bare with me that i'm seriously handicapped in science. However, i assure you i am willing to learn, all i need is time. Giving me a chance is all the support i need and i will be very thankful for that. =) think i vomitted enough already. hahas. On to next post!
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Atoms, Moles & Stoichiometry.

thoughts: 2 march, 9'44pm.
Just realised something bad, i have near-zero science foundation. Sighs, i have to buck up more and revised O'level"s syllabus already. There'll be test tomorrow too and i think i might flang it though, =x. oh wells enough chitty-chatty, i'll do as much as i can to study a bit for the test.


Atoms, Moles & Stoichiometry: 9'57pm.
(i'm quite surprised that the notes were easy enough for me to understand every word, thanks for the notes ms jee!)

Basically this set of notes start by re-introducing the SI(Systeme International) system, the 7 basic SI Units and a few non-SI units used in chemistry stated below:

Name:..........................Symbol:........Quantity:
Minute.........................min.............time
Atomic mass unit.......u..................mass
Bar...............................bar..............pressure
Atmosphere................atm.............pressure

Then it goes onto the Derived units used in chemistry..
Pascal, Joule, Coulumb, Volt, degree celsius, etc.
As it continues it also covers on how to answer some calculations with respect to certain significant number.


Then it comes to the key conclusion on how to calculate the products formed after the process. Like stated in the example; CaCO3(s) ----> CaO(s) + CO2(g)

Mr of CaCO3(s) = 40.1 +12.0 + (16.0 x 3)
..........................= 100.1

Mr of CaO = 40.1 + 16.0
...................= 56.1

No. of mole of CaCO3 = 25.0/100.1
.....................................= 0.2497 mol

Since 1 mol CaCO3 produces 1 mol CaO,
.: No. of mole of CaO = 0.2497 mol.

Mass of CaO = 0.2479 x 56.
.......................= 14.01 g
.......................~ 14.0 g (3 s.f)


*yeah, that sums up all the info in the notes. Time to sleep! I left some definitions below for referance, feel free to keep readind. =) chal people!



DEFINITIONS:
atom: the smallest component of an element having the chemical properties of the element, consisting of a nucleus containing combinations of neutrons and protons and one or more electrons bound to the nucleus by electrical attraction; the number of protons determines the identity of the element.

moles: The amount of a substance that contains as many atoms, molecules, ions, or other elementary units as the number of atoms in 0.012 kilogram of carbon 12. The number is 6.0225 × 10²³, or Avogadro's number. Also called gram molecule.

stoichiometry: The art or process of calculating the atomic proportions, combining weights, and other numerical relations of chemical elements and their compounds.

Binary Covalent Nomenclature Tutorial

Summary:
Pure substances that consist of two nonmetallic elements.
Hydrogen atoms always form one covalent bond, and halgen atoms usually form one bond.

examples:

e.g. dinitrogen pentoxide: prefix (name of nonmetal) prefix (root of name of nonmetal)ide
e.g. carbon dioxide: (name of nonmetal) prefix (root of name of nonmetal) ide
e.g. hydrogen fluoride: (name of nonmetal) (root of nonmetal) ide

Prefixes:
1 - mon(o) 6 - hex(a)
2 - di 7 - hept(a)
3 - tri 8 - oct(a)
4 - tetr(a) 9 - non(a)
5 - pent(a) 10 - dec(a)

(14:54, O-Hub)

Chemistry Blogger set-up

Today our class were asked to specially set-up a blog for Chemistry lectures.